CHAPTER ONE
Functions of a Real Variable
1.1 Introduction to Functions
The concept of a function is fundamental to calculus and to mathematics generally. Calculus is concerned largely with quantities that vary and with the relationships between such quantities. A function provides a precise mathematical way of expressing one quantity in terms of another.
For example, the area of a square depends on the length of its side. If the side length is represented by x, then the area A is given by
Thus, every permitted value of x determines exactly one value of A. In this situation, the area is said to be a function of the side length.
Similarly, if an object moves at a constant speed of 20 metres per second, the distance travelled after t seconds is
The distance d depends on time t. Consequently, d is a function of t.
Functions occur naturally in science, engineering, economics, statistics, computing and everyday quantitative situations. In calculus, they are particularly important because limits, continuity, differentiation and integration are all developed in relation to functions.
1.2 Meaning and Definition of a Function
A function is a rule or correspondence that assigns to each element of a specified set, called the domain, exactly one element of another specified set, called the codomain.
If a function f maps elements of a set A into a set B, this may be written as
If x∈A and the function assigns the element y∈B to x, then
The element x is called the input or independent variable, while f(x) is the corresponding output or value of the function.
Each permissible input must have exactly one output. Different inputs are allowed to have the same output, but a single input cannot be assigned two different outputs by the same function.
Consider the rule
If x=1, then f(1)=5. If x=4, then f(4)=11. Every chosen value of x produces exactly one corresponding value.
1.3 Function Notation and Evaluation
The notation f(x) is read as “f of x.” It does not mean f multiplied by x. Rather, it denotes the value produced by the function f when the input is x.
Suppose
To determine f(2), every occurrence of x is replaced by 2:
Therefore,
Question: Given f(x)=2x2-5x+4, find f(3).
Given:
Required: f(3).
Solution: Substitute x=3:
Answer: f(3)=7.
Evaluation at Algebraic Inputs
The input of a function need not be a numerical value. It may itself be an algebraic expression.
Question: If f(x)=x2+2x-1, determine f(x+1).
Solution:
Replace every occurrence of x in the function by x+1:
Expand:
Collect like terms:
Answer: x2+4x+2.
Difference Quotient
An expression that will become particularly important when differentiation is introduced is
It measures an average rate of change over an interval of length h.
Question: If f(x)=x2, simplify
Solution:
Hence,
Since h≠0, divide by h:
Answer: 2x+h.
1.4 Domain, Codomain and Range
A function is not completely described merely by writing a formula. The values that may be used as inputs and the values that may occur as outputs are also important.
The domain of a function is the set of all permissible input values for which the function is defined.
The codomain is the specified set into which the outputs of the function are required to fall.
The range is the set of actual output values produced by the function as the input varies throughout its domain.
The range is therefore contained in the codomain, but the two need not be equal.
Finding the Domain of an Algebraic Function
When no domain is explicitly stated, the natural real domain is usually taken to be all real numbers for which the formula has a real, defined value.
For polynomial functions there is no restriction on real x. Rational functions exclude values that make a denominator zero. Functions involving an even root require the quantity inside the root to be non-negative.
Question: Find the domain of
Solution:
The denominator must not equal zero:
Therefore,
Answer:
Question: Determine the domain of
Solution:
For the square root to be real,
Answer:
Question: Find the domain of
Solution:
Two restrictions must be satisfied.
For the square root:
so that
For the denominator:
so that x≠5.
Answer:
Determining a Range
Question: Find the range of f(x)=x2+1, where x∈ℝ.
Solution:
For every real number x,
Therefore,
The minimum value of the function is 1, attained when x=0. Every value greater than 1 can also be produced.
Answer:
1.5 Functions of a Real Variable
A real-valued function of a real variable is a function whose domain is a subset of the real numbers and whose values are real numbers.
Such a function may be represented in the form
where D⊆ℝ.
For example,
defines a real-valued function for every real number x. Its natural domain is ℝ.
In contrast,
is real-valued only when x-2>0. The inequality is strict because the expression inside the square root must be positive and the resulting denominator must not be zero. Hence,
Functions of a real variable form the main objects studied in elementary calculus.
1.6 Types of Real Functions
Real functions can be classified according to the form of the rule that defines them. Familiarity with these classes is important because later techniques of limits, differentiation and integration depend partly on the type of function involved.
Constant Functions
A constant function has the form
where c is a fixed real number. Its value does not change when x changes.
For example,
Identity Function
The identity function is defined by
Every input is returned unchanged.
Linear Functions
A linear function in elementary coordinate form is commonly written as
where m and c are constants. Its graph is a straight line, and m represents the slope.
Polynomial Functions
A polynomial function has the general form
where n is a non-negative integer and the coefficients are constants.
Examples include
and
Rational Functions
A rational function is a quotient of two polynomial functions:
where Q(x)≠0.
Since
the domain excludes x=2 and x=-2.
Radical Functions
A radical function contains a variable within a root. For example,
For a real-valued square-root function,
so the domain is [-4,∞).
Absolute-Value Functions
The absolute-value function is defined by
Thus |x| represents the non-negative distance of x from zero on the real number line.
Exponential Functions
An exponential function has the form
where a>0 and a≠1.
Examples include 2x, 10x and ex.
Logarithmic Functions
The logarithmic function
is the inverse of the exponential function ax, where a>0 and a≠1. Its real domain is
Trigonometric Functions
The basic trigonometric functions include
They are especially important in calculus because they describe periodic behaviour and arise naturally in geometry, waves, oscillations and rotational motion.
| Function Type | Typical Form | Basic Domain Information |
|---|---|---|
| Constant | f(x)=c | Usually all real numbers |
| Polynomial | P(x) | All real numbers |
| Rational | P(x)/Q(x) | Exclude zeros of Q(x) |
| Square-root | √g(x) | Require g(x)≥0 |
| Exponential | ax | All real numbers |
| Logarithmic | logax | x>0 |
1.7 Equality of Functions
Two functions are equal if they have the same domain and produce the same output for every input in that domain.
For example, consider
and
Since expansion gives
and both functions have domain ℝ, the two functions are equal.
However, formulas that simplify to the same algebraic expression need not define equal functions if their domains differ.
Consider
and
Since
f(x)=x+1 whenever x≠1. Nevertheless, f is undefined at x=1, whereas g is defined there. Therefore, with their natural domains, the functions are not equal.
1.8 Operations on Functions
Functions can be combined using the ordinary algebraic operations of addition, subtraction, multiplication and division.
If f and g are functions, then
and
provided g(x)≠0.
Question: Let
Find (f+g)(x) and (fg)(x).
Solution:
For the sum:
For the product:
Expanding:
Answer:
and
1.9 Composite Functions
A function can be applied to the output of another function. This process is called composition of functions.
If f and g are functions for which the relevant values are defined, the composite function f∘g is defined by
The function g acts first, and its output becomes the input of f.
Question: Given
and
find (f∘g)(x) and (g∘f)(x).
Solution:
First,
Substitute g(x)=x2-3 into f:
Next,
Answer:
This example shows that function composition is generally not commutative:
Domain of a Composite Function
For f(g(x)) to be defined, x must first belong to the domain of g, and the resulting value g(x) must belong to the domain of f.
Question: Let
Determine (f∘g)(x) and its domain.
Solution:
For this expression to be real,
Therefore,
Answer:
1.10 One-to-One and Many-to-One Functions
One-to-One Functions
A function f is one-to-one, or injective, if different inputs always produce different outputs.
Equivalently,
Question: Show that f(x)=3x-7 is one-to-one on ℝ.
Solution:
Suppose
Then
Add 7 to both sides:
Divide by 3:
Therefore, f is one-to-one.
Many-to-One Functions
A function is many-to-one when two or more distinct inputs can produce the same output.
For example,
gives
and
Thus, f(x)=x2 is not one-to-one on the whole real line.
1.11 Inverse Functions
An inverse function reverses the action of the original function. If f takes an input x to an output y, then its inverse takes y back to x.
If f is a one-to-one function with a suitable domain and range, its inverse is denoted by f-1 and satisfies
and
for values belonging to the appropriate domains.
The notation f-1(x) means the inverse function. It does not mean 1/f(x).
Finding an Inverse Function
A convenient algebraic procedure is:
- write y=f(x);
- interchange x and y;
- solve the resulting equation for y;
- write the result as f-1(x).
Question: Find the inverse of
Solution:
Write
Interchange x and y:
Solve for y:
Therefore,
Verification:
Answer:
Restricting a Domain to Obtain an Inverse
A function that is not one-to-one on its original domain may sometimes become one-to-one when its domain is restricted.
For example, f(x)=x2 is not one-to-one on ℝ. If its domain is restricted to x≥0, however, it becomes one-to-one and its inverse is
Question: Let f(x)=x2+1 for x≥0. Find f-1(x).
Solution:
Interchange x and y:
Hence,
Because the original function is restricted to non-negative inputs, the inverse must return non-negative values:
Therefore,
Answer: f-1(x)=√(x-1) with domain [1,∞).
1.12 Applications of Functions
Functions provide mathematical models for relationships between changing quantities. A mathematical model identifies the relevant variables and expresses one variable in terms of another.
Cost Function
Question: A small production firm has a fixed daily cost of ₦50,000 and an additional production cost of ₦1,200 per item. Express the total daily cost as a function of the number of items produced, and find the cost of producing 80 items.
Given:
Fixed cost = ₦50,000.
Variable cost per item = ₦1,200.
Let x represent the number of items.
Required: Cost function and cost of 80 items.
Solution:
Total cost equals fixed cost plus variable cost:
For 80 items,
Answer: The cost function is C(x)=50,000+1,200x, and the cost of producing 80 items is ₦146,000.
Area as a Function
Question: A rectangle has perimeter 40 m. Express its area as a function of its length x.
Given:
Required: Area as a function of x.
Solution:
Let the length be x and width be w. Then
Therefore,
so
The area is
Hence,
Therefore,
For a non-degenerate rectangle, both dimensions must be positive, so the physically meaningful domain is
Answer:
Temperature Conversion as a Function
The Celsius temperature C corresponding to a Fahrenheit temperature F is given by
Question: Find the Celsius temperature corresponding to 95°F.
Formula:
Solution:
Answer: 95°F=35°C.
Functions and the Development of Calculus
The ideas introduced in this chapter provide the language needed for the remainder of calculus. When a function is represented graphically, its behaviour becomes visible. Limits will allow the behaviour of a function near a point to be studied precisely. Continuity will describe whether the function behaves without a break at a point. Differentiation will measure how rapidly the function changes, while integration will provide methods for accumulation and for determining quantities such as areas and volumes.
For this reason, a sound understanding of functions, domains, ranges, compositions and inverses is not merely preliminary algebra. These ideas form part of the conceptual foundation on which elementary calculus is built.
Chapter Summary
- A function assigns exactly one output to each permissible input.
- The notation f(x) denotes the value of the function f at the input x.
- The domain is the set of permissible inputs, the codomain is the specified target set, and the range is the set of outputs actually produced.
- A real-valued function of a real variable has a domain contained in ℝ and produces real-number outputs.
- Important classes of functions include constant, identity, linear, polynomial, rational, radical, absolute-value, exponential, logarithmic and trigonometric functions.
- Polynomial functions are defined for every real input, while rational and radical functions may have restrictions on their natural real domains.
- Two functions are equal only when their domains agree and they give the same output at every point of that domain.
- Functions may be combined by addition, subtraction, multiplication and division, subject to the appropriate domain restrictions.
- The composition (f∘g)(x)=f(g(x)) applies g first and then f.
- Function composition is generally not commutative.
- A one-to-one function assigns different outputs to different inputs and can possess an inverse on the appropriate domain and range.
- The inverse function reverses the action of the original function and is denoted by f-1.
- Functions provide mathematical models for relationships among changing quantities and form the foundation for graphs, limits, continuity, differentiation and integration.
CHAPTER TWO
Graphs of Functions
2.1 Introduction to Graphs of Functions
A graph provides a visual representation of the relationship between the input and output values of a function. While an algebraic formula tells us how a function is defined, its graph often reveals features that are less obvious from the formula alone, such as where the function increases or decreases, where it crosses the coordinate axes, whether it is symmetric, and how rapidly it changes.
If a function is given by
then its graph is the set of all points
in the Cartesian plane for values of x belonging to the domain of the function.
The graph of a function f is the set of all ordered pairs (x,f(x)) corresponding to permissible values of x.
Graphs are especially important in calculus because the ideas of limits, continuity, derivatives, maxima, minima and area under a curve all have clear graphical interpretations.
2.2 The Cartesian Coordinate Plane
The Cartesian coordinate plane is formed by two perpendicular number lines:
- the horizontal axis, called the x-axis;
- the vertical axis, called the y-axis.
The point at which the axes intersect is called the origin and is denoted by
Every point in the plane is represented by an ordered pair
The first coordinate specifies horizontal position and the second coordinate specifies vertical position.
The Four Quadrants
| Quadrant | Sign of x | Sign of y |
|---|---|---|
| I | Positive | Positive |
| II | Negative | Positive |
| III | Negative | Negative |
| IV | Positive | Negative |
(3,4) lies in Quadrant I.
(-2,5) lies in Quadrant II.
(-4,-1) lies in Quadrant III.
(6,-3) lies in Quadrant IV.
2.3 Plotting Points and Reading Coordinates
To plot a point (x,y), begin at the origin. Move horizontally according to the value of x, then move vertically according to the value of y.
For example, to plot
move four units to the right and then three units upward.
To plot
move two units to the left and then five units downward.
To graph a function numerically, one may first construct a table of selected input values and their corresponding outputs.
Question: Construct a table of values for y=x+2 when x=-2,-1,0,1,2.
Solution:
| x | y=x+2 | Point |
|---|---|---|
| -2 | 0 | (-2,0) |
| -1 | 1 | (-1,1) |
| 0 | 2 | (0,2) |
| 1 | 3 | (1,3) |
| 2 | 4 | (2,4) |
Plotting these points and joining them produces a straight line.
2.4 Graphs of Linear Functions
A linear function in coordinate form is commonly written as
where m is the slope or gradient and c is the y-intercept.
If two distinct points on a line are (x1,y1) and (x2,y2), then the slope is
A positive slope means the line rises from left to right, while a negative slope means it falls.
Question: Find the slope of the line passing through (1,3) and (5,11).
Given:
Formula:
Solution:
Answer: The slope is 2.
Equation of a Line Through a Point
If a line has slope m and passes through (x1,y1), then
Question: Find the equation of the line with slope 3 passing through (2,5).
Formula:
Solution:
Answer: y=3x-1.
Parallel and Perpendicular Lines
Two non-vertical lines are parallel if they have equal slopes:
Two non-vertical lines are perpendicular if
Question: Find the slope of a line perpendicular to y=4x+7.
Solution:
The given line has slope 4. If the perpendicular slope is m, then
Hence,
Answer: -1/4.
2.5 Graphs of Quadratic Functions
A quadratic function has the form
Its graph is called a parabola.
If a>0, the parabola opens upward. If a<0, it opens downward.
The Vertex and Axis of Symmetry
For
the x-coordinate of the vertex is
The corresponding y-coordinate is obtained by substituting this value into the function.
The vertical line
is the axis of symmetry.
Question: Find the vertex of
Given:
Formula:
Solution:
Substitute x=3:
Answer: The vertex is (3,-4).
Intercepts of a Quadratic Graph
The y-intercept is obtained by setting x=0. The x-intercepts are obtained by solving
Question: Find the intercepts of
For the y-intercept:
Hence the y-intercept is
For the x-intercepts:
Therefore,
Answer: The x-intercepts are (2,0) and (3,0), while the y-intercept is (0,6).
Completing the Square and Graph Form
A quadratic function can often be written in the form
The vertex is then immediately visible as
Question: Rewrite y=x2-4x+7 in vertex form.
Solution:
Complete the square:
Therefore,
Answer: The vertex form is y=(x-2)2+3, so the vertex is (2,3).
2.6 Graphs of Polynomial Functions
A polynomial function may have degree 0, 1, 2, 3 or higher. The degree strongly influences the general shape of its graph.
A polynomial of degree n can have at most n real zeros and at most n-1 turning points.
For example, the cubic function
passes through the origin, is negative for negative x, and positive for positive x.
By contrast,
is non-negative for every real value of x and is symmetric about the y-axis.
Zeros of a Polynomial and Graph Intersections
A zero of a polynomial function is a value of x for which
Graphically, a real zero corresponds to an x-intercept.
Question: Find the x-intercepts of
Solution:
Set f(x)=0:
Factorise:
Hence,
Answer: The graph crosses or meets the x-axis at (-2,0), (0,0) and (2,0).
2.7 Graphs of Rational Functions
A rational function is of the form
where P and Q are polynomials and Q(x)≠0.
Rational functions may have values of x at which the function is undefined. These excluded values are often associated with vertical asymptotes or removable holes.
Vertical Asymptotes
For the function
the denominator is zero at x=2. The function becomes arbitrarily large in magnitude as x approaches 2 from either side. The line
is a vertical asymptote.
Horizontal Asymptotes
For
the function approaches zero as |x| becomes large. Thus,
is a horizontal asymptote.
Question: Identify the basic asymptotes of
Solution:
The denominator is zero when
so
is the vertical asymptote.
As |x| becomes very large, 3/(x+1) approaches zero, so
is the horizontal asymptote.
Answer: Vertical asymptote: x=-1; horizontal asymptote: y=2.
2.8 Graphs of Absolute-Value Functions
The basic absolute-value function is
It may be written piecewise as
Its graph is V-shaped, with vertex at the origin.
A more general function
has vertex
Question: State the vertex of y=|x-3|-2.
Solution:
Comparing with
we have h=3 and k=-2.
Answer: The vertex is (3,-2).
2.9 Graphs of Exponential and Logarithmic Functions
Exponential Functions
An exponential function has the form
where a>0 and a≠1.
If a>1, the function increases as x increases. If 0<a<1, the function decreases as x increases.
Every exponential graph of this form passes through
because
Its range is (0,∞), and y=0 is a horizontal asymptote.
Question: Evaluate y=2x for x=-2,-1,0,1,2.
Solution:
| x | 2x |
|---|---|
| -2 | 1/4 |
| -1 | 1/2 |
| 0 | 1 |
| 1 | 2 |
| 2 | 4 |
These values show the rapid growth characteristic of an exponential function with base greater than 1.
Logarithmic Functions
The logarithmic function
is the inverse of
Its domain is (0,∞) and its range is ℝ.
The graph passes through
because
The line x=0 is a vertical asymptote.
The graphs of y=ax and y=logax are reflections of each other in the line y=x.
2.10 Graphs of Trigonometric Functions
The basic trigonometric functions are periodic. Their graphs therefore repeat after fixed intervals.
The Sine Function
The function
has range
and period
Its zeros occur at
where n is an integer.
| x | 0 | π/2 | π | 3π/2 | 2π |
|---|---|---|---|---|---|
| sin x | 0 | 1 | 0 | -1 | 0 |
The Cosine Function
The function
also has range [-1,1] and period 2π.
| x | 0 | π/2 | π | 3π/2 | 2π |
|---|---|---|---|---|---|
| cos x | 1 | 0 | -1 | 0 | 1 |
The Tangent Function
The function
has period
It is undefined when
that is, at
where n is an integer.
These values correspond to vertical asymptotes of the tangent graph.
2.11 Intercepts and Symmetry
x-Intercepts
An x-intercept occurs where the graph meets the x-axis. At such a point,
Therefore, the x-intercepts of y=f(x) are obtained by solving
y-Intercepts
A y-intercept occurs where the graph meets the y-axis. At such a point,
Therefore, if 0 belongs to the domain, the y-intercept is
Question: Find the intercepts of
For the x-intercept:
Hence the x-intercept is (3,0).
For the y-intercept:
Answer: x-intercept = (3,0); y-intercept = (0,-6).
Symmetry About the y-Axis
A function is even if
The graph of an even function is symmetric about the y-axis.
For f(x)=x2,
Therefore, f(x)=x2 is even.
Symmetry About the Origin
A function is odd if
The graph of an odd function is symmetric about the origin.
Question: Determine whether f(x)=x3-2x is even, odd or neither.
Solution:
But
Therefore,
Answer: The function is odd.
2.12 Transformations of Graphs
Many graphs can be obtained from a familiar basic graph by shifting, reflecting or stretching it. Understanding transformations reduces the need to construct every graph from a large table of values.
Vertical Translation
If
is shifted upward by k>0, the new graph is
A downward shift by k is represented by
The graph of
is the graph of y=x2 shifted upward by 4 units.
Horizontal Translation
The graph of
is obtained by shifting y=f(x) to the right by h units.
The graph of
is shifted to the left by h units.
Question: Describe the transformation from y=x2 to y=(x-3)2+2.
Solution:
The replacement x→x-3 shifts the graph 3 units to the right.
The addition of 2 shifts the graph 2 units upward.
Answer: Shift 3 units right and 2 units upward.
Reflection in the x-Axis
The graph of
is the reflection of y=f(x) in the x-axis.
Reflection in the y-Axis
The graph of
is the reflection of y=f(x) in the y-axis.
Vertical Stretch and Compression
For
all y-values are multiplied by a.
If |a|>1, the graph is stretched vertically. If 0<|a|<1, it is compressed vertically.
Horizontal Stretch and Compression
For
the horizontal scale is altered by the factor 1/|b|.
If |b|>1, the graph is compressed horizontally. If 0<|b|<1, it is stretched horizontally.
| Transformation | Effect on y=f(x) |
|---|---|
| y=f(x)+k | Shift upward by k |
| y=f(x)-k | Shift downward by k |
| y=f(x-h) | Shift right by h |
| y=f(x+h) | Shift left by h |
| y=-f(x) | Reflect in x-axis |
| y=f(-x) | Reflect in y-axis |
| y=af(x) | Vertical scaling |
| y=f(bx) | Horizontal scaling by factor 1/|b| |
2.13 Reading and Interpreting Graphs
A graph should be interpreted as mathematical information rather than merely as a picture. Important features include the domain, range, intercepts, intervals of increase or decrease, turning points, maximum and minimum values, symmetry and asymptotic behaviour.
Increasing and Decreasing Behaviour
A function is increasing on an interval if its output values rise as the input values increase. It is decreasing on an interval if its output values fall as the input values increase.
For example,
decreases as x moves from negative values toward zero, reaches a minimum at x=0, and then increases for positive x.
Maximum and Minimum Values
A graph may possess a highest or lowest value over part or all of its domain.
Question: Determine the minimum value of
Solution:
Complete the square:
Since
the smallest possible value of f(x) is obtained when x=2.
Answer: The minimum value is 3, occurring at x=2.
Intersections of Two Graphs
If two functions
and
intersect, their y-values are equal at the point of intersection. Hence, the x-coordinates of intersections satisfy
Question: Find the points of intersection of
and
Solution:
At an intersection,
Rearrange:
Factorise:
Therefore,
When x=3:
When x=-1:
Answer: The graphs intersect at (3,9) and (-1,1).
Graphs as Preparation for Calculus
The graph of a function provides an intuitive introduction to several central ideas in calculus. A graph can suggest whether a function approaches a particular value near a point, which leads to the concept of a limit. A graph without a break at a point suggests continuity. The steepness of a graph introduces the idea of a derivative, while the region between a curve and an axis leads naturally to integration.
For this reason, graphical understanding complements algebraic manipulation. A reliable study of calculus requires both: algebra provides exact symbolic methods, while graphs reveal the behaviour and structure of functions.
Chapter Summary
- The graph of a function f is the set of points (x,f(x)).
- The Cartesian plane consists of the x-axis, y-axis, origin and four quadrants.
- A linear function y=mx+c has a straight-line graph with slope m and y-intercept c.
- The slope between two points is (y2-y1)/(x2-x1).
- A quadratic function has a parabolic graph, with axis of symmetry x=-b/(2a).
- Real zeros of a function correspond to x-intercepts of its graph.
- Rational functions may have vertical and horizontal asymptotes.
- The graph of an absolute-value function is characteristically V-shaped.
- Exponential and logarithmic functions are inverse functions and their graphs are reflections in the line y=x.
- Sine and cosine have period 2π, while tangent has period π.
- x-intercepts are found by solving f(x)=0, while the y-intercept is found from f(0) when defined.
- Even functions are symmetric about the y-axis, while odd functions are symmetric about the origin.
- Translations, reflections and scalings produce new graphs from familiar parent functions.
- Graphs reveal important behaviour such as increasing and decreasing intervals, turning points, extrema, intercepts, symmetry and asymptotes.
- The graphical study of functions provides essential preparation for limits, continuity, differentiation and integration.
CHAPTER THREE
Limits of Functions
3.1 Introduction to Limits
The concept of a limit is one of the central ideas of calculus. It provides a precise way of describing the value that a function approaches when the independent variable approaches a particular point. Limits make it possible to study the behaviour of functions even at points where direct substitution is impossible or where the function itself is not defined.
The ideas of continuity, differentiation and integration all depend fundamentally on limits. In differentiation, a derivative is defined as a limit of an average rate of change. In integration, definite integrals can be constructed from limits of sums.
Consider the function
As x approaches 3, the value of f(x) approaches 5. Symbolically,
This statement means that by choosing x sufficiently close to 3, the value of x+2 can be made as close to 5 as desired.
3.2 Intuitive Meaning of a Limit
If the values of f(x) approach a number L as x approaches a number a, then L is called the limit of f(x) as x approaches a.
The notation is
A limit describes what happens to the function near a point. It does not necessarily depend on the actual value of the function at that point.
Consider
The function is undefined at x=2 because the denominator is zero. However,
Therefore, for x≠2,
As x approaches 2, x+2 approaches 4. Hence,
The existence of a limit at x=a does not require the function to be defined at a. A limit concerns the behaviour of the function as x approaches a.
3.3 Limit Notation
The expression
is read as “the limit of f(x) as x approaches a is L.”
The symbol x→a means that x is allowed to take values increasingly close to a, but it need not actually equal a.
3.4 Limits from Tables and Graphs
A limit can often be estimated numerically by constructing a table of function values near the point of interest.
Question: Estimate
Solution:
| x | (x²-4)/(x-2) |
|---|---|
| 1.9 | 3.9 |
| 1.99 | 3.99 |
| 1.999 | 3.999 |
| 2.001 | 4.001 |
| 2.01 | 4.01 |
| 2.1 | 4.1 |
From both sides of x=2, the function values approach 4.
Answer:
Graphical Interpretation
On a graph, the statement
means that the points on the graph approach a height of L as their x-coordinates approach a from both sides.
The actual point (a,f(a)) may lie at (a,L), may lie somewhere else, or may not exist at all. The limit depends on the nearby behaviour.
3.5 Left-Hand and Right-Hand Limits
A two-sided limit examines the behaviour of a function as x approaches a point from both directions.
Left-Hand Limit
The left-hand limit of f(x) as x approaches a is the value approached by f(x) when x approaches a through values less than a.
Right-Hand Limit
The right-hand limit of f(x) as x approaches a is the value approached by f(x) when x approaches a through values greater than a.
A finite two-sided limit exists precisely when both one-sided limits exist and are equal:
if and only if
Question: Consider
Determine the left-hand limit, right-hand limit and two-sided limit at x=2.
Solution:
From the left:
From the right:
Since
the two-sided limit does not exist.
Answer:
therefore
does not exist.
3.6 Laws of Limits
Limit laws allow complicated limits to be evaluated from simpler ones. Suppose
and
Then, whenever the resulting expressions are defined, the following laws apply.
| Law | Formula |
|---|---|
| Constant Law | limx→a c = c |
| Sum Law | lim(f+g)=L+M |
| Difference Law | lim(f-g)=L-M |
| Constant Multiple Law | lim(cf)=cL |
| Product Law | lim(fg)=LM |
| Quotient Law | lim(f/g)=L/M, provided M≠0 |
| Power Law | lim[f(x)]n=Ln |
| Root Law | lim √[n]{f(x)}=√[n]{L}, where defined |
Question: Evaluate
Solution:
Polynomial functions satisfy the limit laws directly, so substitute x=2:
Answer:
3.7 Direct Substitution
For many elementary functions, the first method to try when evaluating a finite limit is direct substitution.
If substituting x=a produces an ordinary real number, then that number is often the required limit.
Question: Evaluate
Solution:
Answer: 55.
Question: Evaluate
Solution:
The denominator does not vanish at x=1, so direct substitution is valid:
Answer: 4/7.
3.8 Indeterminate Forms and Algebraic Simplification
Sometimes direct substitution produces the expression
This is called an indeterminate form. It does not mean that the limit is zero, nor does it mean that the limit is automatically undefined. Instead, it indicates that further simplification is required before the limit can be determined.
The form 0/0 is not a numerical answer. It signals that the numerator and denominator are both tending to zero and that their relative behaviour must be examined.
Common techniques for resolving elementary 0/0 forms include factorisation, cancellation and rationalisation.
3.9 Limits Involving Factorisation
Question: Evaluate
Solution:
Direct substitution gives
Factorise the numerator:
Therefore, for x≠3,
Hence,
Answer: 6.
Question: Evaluate
Solution:
Use the difference of cubes:
Therefore,
for x≠2.
Now substitute x=2:
Answer: 12.
Question: Evaluate
Solution:
Factorise both numerator and denominator:
Hence, for x≠1,
Therefore,
Answer: 3/2.
3.10 Limits Involving Rationalisation
When square roots occur and direct substitution gives 0/0, multiplication by a conjugate often removes the indeterminate form.
Question: Evaluate
Solution:
Direct substitution produces 0/0. Multiply numerator and denominator by the conjugate √x+2:
The numerator becomes
Hence,
for x≠4.
Therefore,
Answer: 1/4.
Question: Evaluate
Solution:
Multiply by the conjugate:
The numerator becomes
Therefore, for x≠0,
Thus,
Answer: 1/6.
3.11 Limits Involving Trigonometric Functions
Two important limits used frequently in elementary calculus are
and
where the angle x is measured in radians.
The standard trigonometric limit limx→0(sin x)/x=1 holds in this form when x is measured in radians.
Question: Evaluate
Solution:
Write
As x→0, 5x→0. Therefore,
Answer: 5.
Question: Evaluate
Solution:
Rewrite as
As x→0,
and
Hence,
Answer: 3/2.
Question: Evaluate
Solution:
Multiply numerator and denominator by 1+cos x:
Using
we obtain
This can be written as
Therefore,
Answer: 1/2.
3.12 Infinite Limits and Vertical Asymptotes
A function may increase or decrease without bound as x approaches a particular value. Such behaviour is described using an infinite limit.
For example,
becomes arbitrarily large and positive as x approaches zero from either side. Hence,
This notation indicates unbounded growth; it does not mean that infinity is an ordinary real number.
If f(x) becomes unbounded as x approaches a from one or both sides, the line x=a is called a vertical asymptote of the graph.
Question: Examine the one-sided limits of
as x→3.
Solution:
As x→3+, the denominator is a small positive number, so
As x→3-, the denominator is a small negative number, so
Therefore, x=3 is a vertical asymptote.
3.13 Limits at Infinity
Limits at infinity describe the behaviour of a function when x becomes arbitrarily large in the positive or negative direction.
For example,
As the denominator grows without bound, the fraction approaches zero.
Rational Functions at Infinity
For a rational function, the relative degrees of the numerator and denominator often determine the limit as x→∞ or x→-∞.
| Degrees | Typical Behaviour |
|---|---|
| Degree of numerator < degree of denominator | Limit is 0 |
| Degrees are equal | Limit is the ratio of leading coefficients |
| Degree of numerator > degree of denominator | The function is generally unbounded or requires further analysis |
Question: Evaluate
Solution:
Divide numerator and denominator by x2:
As x→∞,
Therefore,
Answer: 0.
Question: Evaluate
Solution:
Divide numerator and denominator by x2:
As x→∞, the terms involving 1/x and 1/x2 approach zero. Hence,
Answer: 5/2.
Question: Evaluate
Solution:
The numerator has degree 3 while the denominator has degree 2. For large positive x, the dominant behaviour is
Since 2x→+∞ as x→∞,
Answer: The function increases without bound.
Horizontal Asymptotes
If
or
then the line
is a horizontal asymptote in the corresponding direction.
For
the numerator and denominator have the same degree. The ratio of leading coefficients is 3, so
Thus, y=3 is a horizontal asymptote.
3.14 Applications and Significance of Limits
The importance of limits extends beyond the direct evaluation of expressions. Limits provide the mathematical foundation for describing instantaneous change, continuity and accumulation.
Average Rate of Change
For a function f(x), the average rate of change between x=a and x=a+h is
When h is allowed to approach zero, the limiting value, when it exists, gives the instantaneous rate of change. This will lead directly to the derivative.
Question: For f(x)=x2, determine the limit of the average rate of change at x=3 as h→0.
Given:
Required:
Solution:
Therefore,
Now take the limit as h→0:
Answer: The limiting rate of change is 6.
Limits and Continuity
A function behaves continuously at a point when its limiting value agrees with its actual function value there. In symbols, continuity at x=a requires
This relationship will be developed fully in the next chapter.
Limits and Differentiation
The derivative of f at a point x is defined through the limit
provided the limit exists. Thus, the theory of differentiation rests directly on the concept of a limit.
Limits and Integration
A definite integral can also be interpreted through a limiting process in which a region is divided into many narrow subregions and the corresponding sums approach a fixed value. In this way, limits also provide the theoretical basis for the calculation of areas and volumes.
Chapter Summary
- A limit describes the value approached by a function as the independent variable approaches a specified point.
- The notation limx→af(x)=L means that f(x) approaches L as x approaches a.
- A function need not be defined at a point for its limit at that point to exist.
- Limits may be estimated numerically from tables or interpreted graphically.
- The left-hand limit describes behaviour as x approaches from smaller values, while the right-hand limit describes behaviour from larger values.
- A finite two-sided limit exists when the left-hand and right-hand limits exist and are equal.
- The sum, difference, product, quotient, power and root laws allow limits to be combined algebraically under appropriate conditions.
- Direct substitution is the simplest method when substitution produces a defined real number.
- The form 0/0 is indeterminate and usually requires algebraic simplification rather than being treated as an answer.
- Factorisation and rationalisation are important methods for resolving elementary indeterminate forms.
- The fundamental trigonometric limit limx→0(sin x)/x=1 is valid when angles are measured in radians.
- Infinite limits describe unbounded behaviour and are associated with vertical asymptotes.
- Limits at infinity describe the long-term behaviour of a function and may identify horizontal asymptotes.
- For rational functions with numerator degree less than denominator degree, the limit at infinity is zero.
- If numerator and denominator have the same degree, the limit at infinity is the ratio of their leading coefficients.
- Limits provide the mathematical foundation for continuity, differentiation and definite integration.
CHAPTER FOUR
Continuity of Functions
4.1 Introduction to Continuity
Continuity is one of the fundamental ideas used to describe the behaviour of functions. Informally, a function is continuous over a region when its values change without sudden breaks, jumps or interruptions. Although this intuitive description is useful, calculus requires a more precise definition based on limits.
Consider the polynomial function
At x=2,
Also,
Thus, the value approached by the function as x approaches 2 is exactly the value of the function at 2. This agreement between the limiting value and the actual function value is the essential idea of continuity at a point.
Continuity is important because many of the standard procedures of calculus rely on functions behaving predictably. It also provides the bridge between the theory of limits developed in the preceding chapter and the study of derivatives that follows.
4.2 Continuity at a Point
A function f is continuous at x=a if f(a) is defined and
This definition states that the value approached by the function near a must coincide with the actual value assigned to the function at a.
Question: Determine whether f(x)=3x2-2x+1 is continuous at x=2.
Given:
Required: Determine whether f is continuous at x=2.
Solution:
First calculate the function value:
Next calculate the limit:
Therefore,
Answer: The function is continuous at x=2.
4.3 The Three Conditions for Continuity
The definition of continuity at x=a can be expressed through three conditions. All three conditions must be satisfied.
| Condition | Mathematical Statement | Meaning |
|---|---|---|
| 1 | f(a) exists | The function is defined at the point. |
| 2 | limx→af(x) exists | The function approaches one finite value from both sides. |
| 3 | limx→af(x)=f(a) | The limiting value equals the actual function value. |
If any one of these conditions fails, the function is not continuous at the point.
Question: Consider
Is f continuous at x=3?
Solution:
At x=3,
which is undefined. Therefore, the first condition for continuity fails.
However, for x≠3,
Hence,
Although the limit exists, f(3) does not exist.
Answer: The function is not continuous at x=3.
Repairing a Removable Discontinuity
In the preceding example, continuity can be restored by defining
Then the function value and limiting value agree:
This illustrates an important feature of a removable discontinuity: the discontinuity can be eliminated by assigning the function the appropriate value at the missing point.
4.4 Continuity on an Interval
Continuity may be considered not only at a single point but also over an interval.
A function is continuous on an open interval (a,b) if it is continuous at every point of that interval.
For a closed interval [a,b], the endpoints require one-sided conditions.
A function f is continuous on [a,b] if it is continuous at every point of (a,b) and satisfies
and
The function
is continuous throughout its natural domain [0,∞). At the endpoint x=0, continuity is understood from the right:
4.5 One-Sided Continuity
At endpoints of intervals, and especially for piecewise-defined functions, one-sided continuity is useful.
A function is right-continuous at x=a if
Similarly, it is left-continuous at x=a if
Question: Let
Examine continuity at x=2.
Solution:
The function value is
The left-hand limit is
The right-hand limit is
Thus,
so the function is right-continuous at 2. However,
and the two one-sided limits are unequal.
Answer: The function is right-continuous at x=2, but it is not continuous there.
4.6 Continuity of Elementary Functions
Many functions commonly encountered in elementary calculus are continuous throughout their natural domains. Recognising this fact allows many continuity and limit problems to be handled efficiently.
Polynomial Functions
Every polynomial function is continuous for every real number.
For example,
is continuous on
Rational Functions
A rational function
is continuous at every point where
Question: Determine the intervals on which
is continuous.
Solution:
The denominator must not equal zero:
Factorising,
Therefore,
Answer: The function is continuous on
Radical Functions
A square-root function is continuous wherever its radicand is non-negative.
For
the natural domain is
The function is continuous throughout this domain.
Exponential and Logarithmic Functions
Exponential functions of the form
are continuous for every real number.
Logarithmic functions of the form
are continuous for
Trigonometric Functions
The sine and cosine functions are continuous for all real values of their arguments:
The tangent function
is continuous wherever cos x≠0. Thus, it is discontinuous at
| Function Type | Continuity |
|---|---|
| Polynomial | Continuous for all real numbers |
| Rational | Continuous wherever the denominator is non-zero |
| Square-root | Continuous throughout its real domain |
| Exponential | Continuous for all real numbers |
| Logarithmic | Continuous for positive arguments |
| Sine and Cosine | Continuous for all real numbers |
| Tangent | Continuous wherever cos x≠0 |
4.7 Algebra of Continuous Functions
Continuity is preserved under the standard algebraic operations. Suppose f and g are continuous at x=a. Then the following functions are also continuous at a whenever they are defined:
and
provided g(a)≠0.
Question: Explain why
is continuous at x=2.
Solution:
Both x2+1 and x+4 are polynomial functions and are therefore continuous at x=2.
Also,
Therefore, their quotient is continuous at x=2.
Indeed,
Answer: The function is continuous at x=2.
4.8 Continuity of Composite Functions
Continuity is also preserved under suitable composition.
If g is continuous at x=a and f is continuous at g(a), then the composite function f∘g is continuous at a.
In limit form,
Question: Determine whether
is continuous on ℝ.
Solution:
The inner function
is a polynomial and is continuous for all real x.
Furthermore,
The square-root function is continuous for non-negative inputs. Hence the composition is defined and continuous for every real number.
Answer: h(x)=√(x2+5) is continuous on ℝ.
4.9 Discontinuity and Its Types
A function is discontinuous at x=a if it fails to satisfy one or more of the conditions required for continuity at that point.
Several forms of discontinuity occur frequently in elementary calculus.
Removable Discontinuity
A removable discontinuity occurs when the limit exists but the function is either undefined at the point or has a value different from the limiting value.
For example,
is undefined at x=1. For x≠1,
Therefore,
The discontinuity can be removed by defining f(1)=2.
Jump Discontinuity
A jump discontinuity occurs when the left-hand and right-hand limits both exist as finite numbers but are unequal.
Suppose
Then
while
Since these limits differ, the function has a jump discontinuity at x=0.
Infinite Discontinuity
An infinite discontinuity occurs when the function becomes unbounded as the variable approaches a point.
For example,
has an infinite discontinuity at x=2, where the graph has the vertical asymptote
Oscillatory Discontinuity
A function may also fail to approach a single value because it oscillates indefinitely near a point. A standard example is
As x→0, the quantity 1/x grows in magnitude and the sine function oscillates between -1 and 1 increasingly rapidly. Consequently,
does not exist.
| Type | Characteristic Behaviour |
|---|---|
| Removable | The finite limit exists, but the function value is missing or incorrect. |
| Jump | Finite left-hand and right-hand limits exist but are unequal. |
| Infinite | The function becomes unbounded near the point. |
| Oscillatory | The function oscillates without approaching a single limiting value. |
4.10 Continuity of Piecewise-Defined Functions
A piecewise-defined function uses different formulas on different parts of its domain. The main points requiring examination are usually the boundary points where the defining formula changes.
Question: Determine whether
is continuous at x=2.
Solution:
Since x≤2 in the first part,
The left-hand limit is
The right-hand limit is
Thus,
Answer: The function is continuous at x=2.
Question: Determine the continuity at x=1 of
Solution:
The left-hand limit is
The right-hand limit is
Since
the two-sided limit does not exist.
Answer: The function is discontinuous at x=1. The discontinuity is a jump discontinuity.
4.11 Determining Unknown Constants for Continuity
A common application of the definition of continuity is to determine an unknown constant in a piecewise-defined function. The value of the constant is chosen so that the left-hand limit, right-hand limit and function value agree at the joining point.
Question: Find the value of k that makes the function
continuous at x=3.
Required: The value of k.
Solution:
For continuity at x=3,
From the left,
From the right,
Also, because the second rule includes x=3,
For continuity,
Therefore,
Answer: k=2.
Question: Find a so that
is continuous at x=2.
Solution:
For x≠2,
Therefore,
Continuity requires
Since f(2)=a,
Answer: a=4.
Question: Determine the values of a and b for which
is continuous at x=1.
Solution:
Continuity requires both one-sided limits to equal f(1)=3.
From the right,
Hence,
From the left,
Using a=1,
Therefore,
Answer:
4.12 The Intermediate Value Property
One of the important consequences of continuity is that a continuous function cannot move from one value to another without passing through all intermediate values.
If f is continuous on a closed interval [a,b] and N is any number between f(a) and f(b), then there exists at least one number c∈[a,b] such that
A particularly useful case occurs when f(a) and f(b) have opposite signs. In that situation, zero lies between the two function values, so the continuous function must have at least one zero between a and b.
Question: Show that the equation
has at least one real root between 1 and 2.
Solution:
Let
Since f is a polynomial, it is continuous on [1,2].
Evaluate the endpoints:
Since
the Intermediate Value Theorem guarantees that there exists at least one c∈(1,2) such that
Answer: The equation has at least one real root in the interval (1,2).
The Intermediate Value Theorem guarantees the existence of a root in the interval, but it does not by itself give the exact value of that root.
4.13 Continuity and Differentiability
Continuity and differentiability are closely related, but they are not identical concepts. A derivative measures instantaneous rate of change, while continuity describes whether the function value agrees with its limiting behaviour.
An important theorem states:
If a function f is differentiable at x=a, then f is continuous at x=a.
Thus,
The converse is not generally true. A function can be continuous at a point without being differentiable there.
A Continuous Function That Is Not Differentiable
Consider
The function is continuous at x=0 because
However, the graph has a sharp corner at the origin. The slope from the left is -1, while the slope from the right is 1. Therefore, there is no single derivative at x=0.
Hence,
This distinction becomes particularly important when derivatives are studied in the following chapters.
4.14 Applications and Significance of Continuity
Continuity provides a mathematical description of smooth and predictable variation. Many physical quantities are modelled by continuous functions over suitable intervals. Examples include the position of a moving object as a function of time, temperature variation over time, the volume of water in a steadily filled container, and many idealised relationships used in science and engineering.
Using Continuity to Evaluate Limits
If f is known to be continuous at x=a, then
This means that the limit can be evaluated simply by substitution.
Question: Evaluate
Solution:
The polynomial x2+9 is continuous for all real x and is always positive. The square-root function is continuous for positive inputs. Therefore, the composite function is continuous at x=4.
Hence, direct substitution gives
Answer: 5.
Continuity in Mathematical Modelling
Question: The height of water in a tank during a controlled filling process is modelled by
where h is measured in metres and t in hours. Determine the height approached as t→6.
Given:
Required:
Solution:
The function is linear and therefore continuous for all real values of t. Hence,
Answer: The water height approaches 5 metres.
Continuity as Preparation for Differentiation
The derivative is defined through a limiting process. Before a function can be differentiable at an ordinary point, it must first be continuous there. A break, jump or infinite discontinuity prevents the derivative from existing at that point.
For this reason, continuity is an essential checkpoint when analysing the behaviour of a function. In later chapters, continuity will support the study of derivatives, tangents, rates of change, maxima and minima, and curve sketching.
Chapter Summary
- A function f is continuous at x=a when limx→af(x)=f(a).
- Continuity at a point requires that f(a) exists, the limit exists, and the limit equals f(a).
- A function is continuous on an open interval if it is continuous at every point of that interval.
- Continuity on a closed interval also requires appropriate one-sided continuity at its endpoints.
- Right-continuity uses a right-hand limit, while left-continuity uses a left-hand limit.
- Polynomial functions are continuous for all real numbers.
- Rational functions are continuous wherever their denominators are non-zero.
- Radical, logarithmic and trigonometric functions are continuous throughout the appropriate parts of their natural domains.
- Sums, differences, products and constant multiples of continuous functions remain continuous; quotients are continuous where the denominator is non-zero.
- Under suitable conditions, the composition of continuous functions is continuous.
- Important types of discontinuity include removable, jump, infinite and oscillatory discontinuities.
- A removable discontinuity can be repaired when the missing or incorrect function value is replaced by the existing limiting value.
- For a piecewise-defined function to be continuous at a joining point, its left-hand limit, right-hand limit and function value must agree.
- Unknown constants in piecewise functions can be determined by imposing the conditions for continuity.
- The Intermediate Value Theorem guarantees that a continuous function assumes every intermediate value between its values at the endpoints of an interval.
- If a continuous function changes sign over an interval, it must have at least one zero between the two endpoints.
- Differentiability at a point implies continuity at that point, but continuity does not necessarily imply differentiability.
- Continuity provides an essential foundation for differentiation, curve analysis and later applications of calculus.
CHAPTER FIVE
The Derivative and Principles of Differentiation
5.1 Introduction to the Derivative
The derivative is one of the central concepts of differential calculus. It measures how rapidly one quantity changes with respect to another. When a quantity y depends on another quantity x, the derivative expresses the instantaneous rate at which y changes as x changes.
If
then the derivative of f with respect to x may be written as
or
The derivative has both an algebraic and a geometrical interpretation. Algebraically, it is defined by a limit. Geometrically, it gives the slope of the tangent to the graph of a function at a point.
5.2 Average Rate of Change
Before studying instantaneous change, it is useful to consider average change over an interval.
Suppose a function y=f(x) changes from f(x1) to f(x2) as x changes from x1 to x2. The average rate of change is
The average rate of change of f from x=a to x=b is
Question: Find the average rate of change of f(x)=x2+1 from x=2 to x=5.
Formula:
Solution:
Therefore,
Answer: The average rate of change is 7.
Average Rate of Change as Secant Slope
If the points
and
lie on the graph of f, then the average rate of change is also the slope of the secant line joining P and Q.
5.3 Instantaneous Rate of Change
An average rate of change describes change over an interval. In many applications, however, the rate of change at a particular instant or at a particular point is required.
Suppose the interval begins at x and has width h. The average rate of change over the interval is
If h is made smaller and smaller, the second point approaches the first. When the limit exists,
gives the instantaneous rate of change of the function at x.
The derivative of f at x is defined by
provided the limit exists.
5.4 Derivative from First Principles
Differentiation from first principles means finding a derivative directly from its limit definition rather than using an already established differentiation rule.
The basic procedure is:
- find f(x+h);
- form f(x+h)-f(x);
- divide by h;
- simplify;
- take the limit as h→0.
Question: Differentiate f(x)=x2 from first principles.
Formula:
Solution:
Therefore,
Divide by h:
Now take the limit as h→0:
Answer:
Question: Differentiate f(x)=3x+4 from first principles.
Solution:
Then,
Hence,
Therefore,
Answer: f'(x)=3.
Question: Find the derivative of f(x)=x3 from first principles.
Solution:
Expanding,
Thus,
Divide by h:
Taking the limit,
Answer:
5.5 Geometrical Meaning of the Derivative
The derivative has a direct geometrical interpretation. Consider a curve y=f(x) and a point
A second point nearby may be written as
The slope of the secant line through P and Q is
As h→0, the point Q approaches P. If the secant slopes approach a definite value, that value is the slope of the tangent to the curve at P.
Question: Find the slope of the tangent to y=x2 at x=3.
Given:
From first principles,
At x=3,
Answer: The slope of the tangent is 6.
Equation of a Tangent
If the tangent to y=f(x) at x=a has slope f'(a), then its equation is
Question: Find the equation of the tangent to y=x2 at x=2.
Solution:
The point on the curve is
The derivative is
Hence the slope at x=2 is
Using the point-slope form,
Therefore,
Answer: y=4x-4.
Equation of a Normal
The normal is perpendicular to the tangent. If the tangent slope is m, where m≠0, then the normal slope is
Question: Find the equation of the normal to y=x2 at x=2.
Solution:
The tangent slope at x=2 is 4. Therefore,
The point is (2,4). Hence,
Answer:
5.6 Derivative Notation
Several notations are commonly used for derivatives. If y=f(x), then the first derivative may be written as
or
The notation dy/dx is particularly useful when applying differentiation rules because it clearly indicates the variable with respect to which differentiation is being performed.
| Notation | Meaning |
|---|---|
| f'(x) | Derivative of the function f |
| y' | Derivative of y |
| dy/dx | Derivative of y with respect to x |
| d/dx[f(x)] | Differentiation operator applied to f(x) |
5.7 Differentiability
A function f is differentiable at x=a if the finite limit
exists.
Differentiability is a stronger property than continuity. If a function is differentiable at a point, then it must be continuous at that point.
However, continuity does not always imply differentiability.
Failure of Differentiability at a Corner
Consider
At x=0, the function is continuous. But the slope to the left is -1 while the slope to the right is 1. Therefore, the derivative does not exist at the origin.
A derivative may fail to exist at:
- a discontinuity;
- a sharp corner;
- a cusp;
- a point with a vertical tangent in the ordinary finite-derivative sense.
5.8 Derivatives of Constant and Power Functions
Derivative of a Constant
If
where c is a constant, then
This is expected geometrically because the graph of a constant function is horizontal.
The Power Rule
If
then
for values of n and x for which the expression is defined.
Question: Differentiate y=x7.
Solution:
Answer: 7x6.
Question: Differentiate y=1/x3.
Solution:
Rewrite as
Applying the power rule,
Therefore,
Answer: -3/x4.
Question: Differentiate y=√x.
Solution:
Write
Then,
Therefore,
Answer: 1/(2√x).
5.9 Basic Rules of Differentiation
Constant Multiple Rule
If c is a constant, then
Sum Rule
Difference Rule
Question: Differentiate
Solution:
Answer:
Question: Differentiate
Solution:
Rewrite using indices:
Differentiate term by term:
Thus,
Answer:
5.10 Higher-Order Derivatives
The derivative of a function may itself be differentiated. This produces a second derivative. Repeating the process gives higher-order derivatives.
If
then the second derivative may be written as
or
The third derivative may be written as
or
Question: Find the first, second and third derivatives of
Solution:
First derivative:
Second derivative:
Third derivative:
Answer:
5.11 Derivative as Velocity and Acceleration
A major application of differentiation occurs in motion. If the position of a particle at time t is represented by s(t), then velocity is the derivative of position:
Acceleration is the derivative of velocity:
Equivalently,
Question: A particle moves along a straight line with position
metres, where t is measured in seconds. Find its velocity and acceleration at t=2.
Given:
Velocity:
At t=2,
Thus,
Acceleration:
At t=2,
Answer: Velocity = -3 m/s; acceleration = 0 m/s2.
5.12 Significance of the Derivative in Calculus
The derivative provides a precise mathematical description of local change. It determines the slope of a curve, the instantaneous velocity of a moving object, the rate at which one variable changes with respect to another, and the behaviour of a function near a point.
The derivative also provides the foundation for many later applications, including:
- finding tangents and normals;
- determining increasing and decreasing intervals;
- locating maximum and minimum values;
- solving optimization problems;
- analysing motion;
- sketching curves accurately;
- studying rates in physical, economic and biological models.
Chapter Summary
- The derivative measures instantaneous rate of change.
- The average rate of change from a to b is [f(b)-f(a)]/(b-a).
- The derivative is defined by f'(x)=limh→0[f(x+h)-f(x)]/h.
- Differentiation from first principles uses the limit definition directly.
- Geometrically, f'(a) is the slope of the tangent to the graph at x=a.
- The equation of the tangent at x=a is y-f(a)=f'(a)(x-a).
- If the tangent slope is non-zero, the normal slope is its negative reciprocal.
- Common derivative notations include f'(x), y' and dy/dx.
- Differentiability implies continuity, but continuity does not always imply differentiability.
- The derivative of a constant is zero.
- The power rule is d(xn)/dx=nxn-1.
- Sum, difference and constant multiple rules allow polynomial-type expressions to be differentiated efficiently.
- Higher-order derivatives are obtained by repeated differentiation.
- If s(t) is position, then velocity is ds/dt and acceleration is d2s/dt2.
CHAPTER SIX
Techniques of Differentiation
6.1 Introduction to Differentiation Techniques
Differentiation from first principles provides the theoretical foundation of the derivative, but it is not the most efficient method for differentiating complicated functions. Once the fundamental derivative rules have been established, they can be applied systematically to polynomial, rational, trigonometric, exponential, logarithmic and composite functions.
The choice of rule depends on the structure of the function. A product requires the product rule, a quotient usually requires the quotient rule, and a function nested inside another function requires the chain rule.
Before differentiating, first examine the structure of the function. Identify whether it is a sum, product, quotient, power, composition, exponential, logarithmic or trigonometric expression. This determines the most efficient technique.
6.2 Review of the Power, Sum and Difference Rules
For a power function,
If several differentiable terms are added or subtracted, they may be differentiated separately.
Question: Differentiate
Solution:
Answer:
Question: Differentiate
Solution:
Write in index form:
Differentiate term by term:
Therefore,
Answer:
6.3 The Product Rule
When two functions are multiplied together, differentiating each separately and multiplying the results is generally incorrect. The product rule must be used.
If
then
Equivalently,
Question: Differentiate
Given:
Then,
Formula:
Solution:
Answer:
Question: Differentiate
Solution:
Let
Then,
By the product rule,
Answer:
6.4 The Quotient Rule
When one differentiable function is divided by another, the quotient rule provides the derivative.
If
then
provided v≠0.
Question: Differentiate
Given:
Then,
Solution:
Simplify the numerator:
Therefore,
Answer:
Question: Differentiate
Solution:
Let
Then,
Hence,
Answer:
6.5 The Chain Rule
The chain rule is used when one function is contained inside another. Such a function is called a composite function.
Suppose
and
Then y=f(g(x)).
Question: Differentiate
Solution:
Let
Then,
Differentiate with respect to u:
Also,
Therefore,
Substitute u=3x+1:
Answer:
Question: Differentiate
Solution:
Rewrite:
Using the chain rule,
Simplifying,
Answer:
Question: Differentiate
Solution:
The outer function is a fourth power and the inner function is 2x2-3x+5.
Answer:
6.6 Differentiation of Trigonometric Functions
When angles are measured in radians, the fundamental derivatives of the basic trigonometric functions are
| Function | Derivative |
|---|---|
| sin x | cos x |
| cos x | -sin x |
| tan x | sec2x |
| cot x | -csc2x |
| sec x | sec x tan x |
| csc x | -csc x cot x |
Question: Differentiate
Solution:
Answer:
Trigonometric Functions with the Chain Rule
Question: Differentiate
Solution:
The outer function is sine and the inner function is 5x.
Hence,
Answer: 5cos(5x).
Question: Differentiate
Solution:
Using the chain rule,
Therefore,
Answer:
Question: Differentiate
Solution:
Answer:
6.7 Differentiation of Exponential Functions
The natural exponential function has the important property
For a general exponential function,
where a>0 and a≠1.
Question: Differentiate
Solution:
Answer: 5ex.
Question: Differentiate
Solution:
Apply the chain rule:
Therefore,
Answer: 3e3x.
Question: Differentiate
Solution:
Answer: 2xln2.
6.8 Differentiation of Logarithmic Functions
The natural logarithm satisfies
More generally,
Question: Differentiate
Solution:
Let
Then,
Therefore,
Hence,
Answer:
For logarithms to base a,
Question: Differentiate
Solution:
Answer: 1/(x ln10).
6.9 Implicit Differentiation
Not every relationship between x and y is conveniently written in the explicit form y=f(x). Sometimes the variables appear together in one equation. In such cases, implicit differentiation is useful.
The key principle is to differentiate both sides with respect to x, remembering that y is itself a function of x.
Question: If
find dy/dx.
Solution:
Differentiate both sides with respect to x:
Rearrange:
Therefore,
Answer:
Question: If
find dy/dx.
Solution:
Differentiate term by term:
For xy, use the product rule:
Hence,
Collect the derivative terms:
Therefore,
Answer:
6.10 Logarithmic Differentiation
Logarithmic differentiation is useful when a function involves complicated products, quotients or variables occurring in both the base and the exponent.
The method involves taking the natural logarithm of both sides and then differentiating implicitly.
Question: Differentiate
Solution:
Take natural logarithms:
Using the logarithm law,
Differentiate both sides:
Therefore,
Since y=xx,
Answer:
6.11 Differentiation of Composite Algebraic Functions
More complicated functions may require more than one differentiation rule. The most efficient method is to work from the outermost structure inward.
Question: Differentiate
Solution:
The expression is a product, so use the product rule. Let
Differentiate u using the chain rule:
Also,
Therefore,
Answer:
Question: Differentiate
Solution:
This function contains several layers. The outer function is a cube, followed by sine, followed by 2x.
Therefore,
Answer:
Question: Differentiate
Solution:
This is a product. Let
Then,
and
Using the product rule,
Factorising ex,
Answer:
6.12 Higher-Order Derivatives of Standard Functions
Higher-order derivatives are often required in the study of acceleration, curvature, maxima, minima and curve sketching.
Question: Find y'' if
Solution:
First derivative:
Second derivative:
Answer: y''=4e2x.
Question: Find the first four derivatives of y=sin x.
Solution:
The derivatives then repeat in a cycle of four.
Answer:
6.13 Choosing an Appropriate Differentiation Rule
Efficient differentiation depends on recognising the structure of a function before beginning the calculation.
| Structure of Function | Typical Form | Recommended Rule |
|---|---|---|
| Simple power | xn | Power rule |
| Sum or difference | f±g | Differentiate term by term |
| Product | fg | Product rule |
| Quotient | f/g | Quotient rule or algebraic simplification |
| Composite function | f(g(x)) | Chain rule |
| Implicit relation | F(x,y)=0 | Implicit differentiation |
| Variable in base and exponent | xx | Logarithmic differentiation |
| Trigonometric expression | sin x, cos x, tan x | Standard trig derivatives, often with chain rule |
| Exponential expression | eu, au | Exponential derivative and chain rule |
| Logarithmic expression | ln u | Logarithmic derivative and chain rule |
Question: Differentiate
Reasoning:
The entire expression is a quotient of two polynomial functions. Therefore, the quotient rule is appropriate.
Solution:
Expand the numerator:
Hence,
Answer:
Question: Differentiate
Reasoning:
This is an exponential function whose exponent is itself a function of x. Therefore, use the exponential derivative together with the chain rule.
Solution:
Answer:
Chapter Summary
- The power, sum and difference rules form the basis for differentiating many algebraic expressions.
- The product rule is (uv)'=u'v+uv'.
- The quotient rule is (u/v)'=(vu'-uv')/v2.
- The chain rule is used for composite functions and may be written as dy/dx=(dy/du)(du/dx).
- The derivatives of sin x, cos x and tan x are cos x, -sin x and sec2x, respectively.
- Trigonometric derivative formulas in elementary calculus assume that angles are measured in radians.
- The derivative of ex is ex.
- The derivative of ax is axln a.
- The derivative of ln x is 1/x.
- Implicit differentiation is used when x and y occur together in an equation that is not conveniently solved explicitly for y.
- Logarithmic differentiation is especially useful when the variable occurs in both the base and exponent.
- Complicated functions may require several differentiation rules in a single calculation.
- Higher-order derivatives are obtained by differentiating repeatedly.
- Correct rule selection begins by identifying the mathematical structure of the function.
CHAPTER NINE
Definite Integrals and the Fundamental Theorem of Calculus
9.1 Introduction to Definite Integration
Indefinite integration produces a family of antiderivatives. A definite integral, however, produces a numerical value associated with a function over a specified interval. It is one of the principal tools for measuring accumulated change.
If a quantity varies continuously with respect to another quantity, integration can be used to determine its total accumulated effect over an interval. Applications include area, displacement, total production, accumulated flow and volume.
A definite integral has two limits of integration and is written in the form
The numbers a and b are called the lower and upper limits of integration respectively.
9.2 Meaning and Notation of a Definite Integral
If f is integrable on the interval [a,b], then
represents the net accumulation of f(x) over the interval from x=a to x=b.
Unlike an indefinite integral, a definite integral does not require an arbitrary constant C. Once the limits are specified, the result is a definite number.
The expression
represents the net accumulation of the function 2x between x=1 and x=3.
9.3 Definite Integrals as Limits of Sums
The concept of a definite integral originates from the idea of dividing an interval into many small subintervals and adding the contributions from each part.
Suppose [a,b] is divided into n equal subintervals of width
If xi* is a selected point in the ith subinterval, then the sum
approximates the accumulated contribution over the interval.
When the number of subdivisions increases without bound and the widths approach zero, the limiting value is the definite integral:
A finite sum gives an approximation to total accumulation. The definite integral is obtained by taking a limit in which the partition becomes arbitrarily fine.
9.4 Geometrical Interpretation of Definite Integrals
When f(x)≥0 on [a,b], the definite integral
is equal to the area between the graph y=f(x), the x-axis and the vertical lines x=a and x=b.
When the graph lies below the x-axis, the integral contributes negatively. Thus, a definite integral gives signed area or net area, not necessarily the total geometric area.
Regions above the x-axis contribute positively to a definite integral, while regions below the x-axis contribute negatively.
9.5 Properties of Definite Integrals
Definite integrals satisfy several useful algebraic properties.
Equal Limits
Reversal of Limits
Additivity over Intervals
If c lies between a and b, then
Constant Multiple Rule
Sum and Difference Rules
Order Property
If
for every x∈[a,b], then
9.6 The Fundamental Theorem of Calculus
The Fundamental Theorem of Calculus establishes the central connection between differentiation and integration.
If f is continuous on [a,b] and F is any antiderivative of f, so that
then
The notation
means
This theorem is extremely important because it allows definite integrals to be evaluated using antiderivatives instead of calculating limits of sums directly.
Accumulation Form of the Theorem
If
where f is continuous, then
Thus, differentiation and definite integration are inverse processes in a precise mathematical sense.
9.7 Evaluation of Definite Integrals
Question: Evaluate
Solution:
An antiderivative of 2x is
Therefore,
Answer: 8.
Question: Evaluate
Solution:
An antiderivative is
Hence,
At x=2,
At x=0,
Therefore,
Answer: 10.
Question: Evaluate
Solution:
Write
Then,
Therefore,
Answer: 2.
9.8 Definite Integrals Involving Trigonometric Functions
Question: Evaluate
Solution:
An antiderivative of cos x is sin x.
Answer: 1.
Question: Evaluate
Solution:
An antiderivative of sin x is -cos x.
Answer: 2.
Question: Evaluate
Solution:
Hence,
Answer: 1.
9.9 Definite Integrals Involving Exponential Functions
Question: Evaluate
Solution:
Therefore,
Answer: e-1.
Question: Evaluate
Solution:
An antiderivative is
Thus,
Therefore,
Answer:
9.10 Substitution in Definite Integrals
Substitution can be applied directly to definite integrals. When the variable is changed, the limits should also be changed to values corresponding to the new variable.
Question: Evaluate
Solution:
Let
Then,
Change the limits:
When x=0,
When x=1,
Thus,
Answer: 15/4.
Question: Evaluate
Solution:
Let
Change the limits:
When x=0, u=0.
When x=π/8,
Hence,
Answer: 1.
9.11 Symmetry Properties of Definite Integrals
Symmetry can simplify many definite integrals.
Odd Functions
If f is odd, so that
then over a symmetric interval,
Even Functions
If f is even, so that
then
Question: Evaluate
Solution:
Since x3 is an odd function and the interval is symmetric about zero,
Answer: 0.
Question: Evaluate
Solution:
Since x2 is even,
Answer: 16/3.
9.12 Total Change from a Rate Function
If F'(x)=f(x), then the Fundamental Theorem of Calculus gives
This principle is often called the net change theorem. It states that the integral of a rate of change gives the net change in the original quantity.
Question: A particle has velocity
metres per second. Find its displacement from t=0 to t=3.
Formula:
Solution:
An antiderivative is
Therefore,
Answer: The displacement is 15 metres.
Integrating velocity gives displacement, which is a signed quantity. Total distance travelled may require splitting the interval at points where the velocity changes sign and integrating the magnitude of the velocity.
9.13 Average Value of a Function
If f is integrable on [a,b], its average value on the interval is
Question: Find the average value of
on the interval [0,3].
Formula:
Solution:
Hence,
Answer: The average value is 3.
9.14 Significance of Definite Integration
Definite integration provides a rigorous method for calculating accumulated quantities over intervals. Its importance lies not only in area calculations but in its ability to convert rates into totals.
For example, integrating velocity over time gives displacement, integrating a flow rate gives total volume, and integrating a density over a region can give total mass under appropriate conditions.
The Fundamental Theorem of Calculus makes these calculations practical by connecting accumulated change to antiderivatives.
Chapter Summary
- A definite integral gives the net accumulation of a function over a specified interval.
- The notation ∫abf(x)dx contains lower and upper limits of integration.
- Definite integrals can be defined as limits of sums.
- When f(x)≥0, a definite integral represents the area beneath the graph over the interval.
- Regions below the x-axis make negative contributions to a definite integral.
- Reversing the limits changes the sign of the integral.
- Definite integrals are additive over adjacent intervals.
- The Fundamental Theorem of Calculus states that ∫abf(x)dx=F(b)-F(a) when F'(x)=f(x).
- Substitution may be used in definite integrals, with corresponding changes to the limits.
- The integral of an odd function over a symmetric interval is zero.
- The integral of an even function over [-a,a] is twice its integral over [0,a].
- Integrating a rate function over an interval gives the net change in the associated quantity.
- The average value of f on [a,b] is 1/(b-a)∫abf(x)dx.
CHAPTER TEN
Applications of Definite Integrals to Areas and Volumes
10.1 Introduction to Applications of Definite Integrals
One of the most important applications of definite integration is the measurement of geometric quantities. Areas bounded by curves and volumes of solids generated by rotation can often be calculated exactly using definite integrals.
The central principle is accumulation. A region or solid is imagined as being divided into many extremely small parts. The contribution of each small part is expressed mathematically, and integration adds these contributions over the required interval.
In area problems, the essential quantity is usually a vertical or horizontal strip. In volume problems, the basic element may be a thin disk, washer or cylindrical shell.
10.2 Area Under a Curve
Suppose f(x)≥0 on [a,b]. The area under the curve y=f(x) and above the x-axis is
Question: Find the area under the curve
between x=0 and x=2.
Given:
Formula:
Solution:
Answer: The area is 8/3 square units.
Question: Find the area under
from x=1 to x=4.
Solution:
Answer: 18 square units.
10.3 Area Between a Curve and the x-Axis
If a function is entirely above the x-axis on the interval, its definite integral gives the geometric area directly.
If the function is entirely below the x-axis, however, the definite integral is negative. Geometric area must be positive, so the magnitude of the integral is taken.
Question: Find the area between the curve
and the x-axis from x=0 to x=2.
Solution:
On [0,2], the function x-3 is negative.
The negative sign indicates that the region lies below the axis. Therefore, the geometric area is
Answer: 4 square units.
10.4 Total Area When a Curve Crosses the x-Axis
If a curve crosses the x-axis within the interval, a single definite integral gives net signed area rather than total geometric area. The interval must therefore be divided at the zeros of the function.
Question: Find the total area between
and the x-axis from x=0 to x=3.
Solution:
First find where the curve crosses the axis:
The function is negative on [0,1] and positive on [1,3].
Area below the axis:
Area above the axis:
Total area:
Answer: The total area is 5/2 square units.
10.5 Area Between Two Curves
Suppose two functions y=f(x) and y=g(x) bound a region between x=a and x=b, with
Then the area between the curves is
In words: upper curve minus lower curve.
Question: Find the area enclosed by
and
Solution:
First determine the points of intersection:
Hence,
Between 0 and 2, 2x lies above x2. Therefore,
Answer: The enclosed area is 4/3 square units.
Question: Find the area enclosed between
and
Solution:
Determine the intersections:
Thus,
Over this interval, the line y=x+2 lies above the parabola.
An antiderivative is
At x=2,
At x=-1,
Hence,
Answer: The area is 9/2 square units.
10.6 Determining the Limits of Integration
In many area problems, the limits of integration are not provided directly. They must be obtained by finding where the bounding curves intersect.
If the curves are
and
their intersection points satisfy
Question: Find the limits of integration for the region enclosed by
and
Solution:
Thus,
Answer: The limits of integration are 0 and 4.
10.7 Areas with Respect to y
Some regions are more conveniently described by horizontal strips rather than vertical strips. In that case, the curves are written in the form
and
If the right-hand curve is x=f(y) and the left-hand curve is x=g(y), then
In words: right curve minus left curve.
Question: Find the area bounded by
and
Solution:
Determine the intersections:
Hence,
For 0≤y≤2, the right-hand curve is x=2y and the left-hand curve is x=y2.
Answer: 4/3 square units.
10.8 Introduction to Volumes of Solids of Revolution
A plane region can generate a three-dimensional solid when rotated about a line. Such a solid is called a solid of revolution.
For example, rotating a region under a curve about the x-axis may produce a solid whose cross-sections perpendicular to the axis are circular disks.
Definite integration allows the volumes of such solids to be obtained by summing the volumes of extremely thin elements.
10.9 Volume by the Disk Method
Suppose a region under the curve
from x=a to x=b is rotated about the x-axis and f(x)≥0.
A typical cross-section is a circular disk of radius
Its area is
Therefore, the volume is
Question: Find the volume obtained when the region under
from x=0 to x=2 is rotated about the x-axis.
Formula:
Solution:
Answer: The volume is 8π/3 cubic units.
Question: Find the volume generated by rotating the region under
from x=0 to x=4 about the x-axis.
Solution:
Answer: 8π cubic units.
10.10 Volume by the Washer Method
If the rotating region does not extend all the way to the axis of rotation, each cross-section may have a hole. Such a cross-section is called a washer.
If R(x) is the outer radius and r(x) the inner radius, then the cross-sectional area is
Therefore,
Question: The region between
and
for 0≤x≤2 is rotated about the x-axis. Find the volume.
Solution:
Outer radius:
Inner radius:
Therefore,
Expand:
Hence,
Answer: The volume is 20π/3 cubic units.
10.11 Rotation About the y-Axis
When a region is rotated about the y-axis, one possible method is to write x as a function of y and use horizontal disks or washers.
If
is rotated about the y-axis, the disk formula becomes
Question: Find the volume obtained by rotating the region bounded by
and 0≤y≤2 about the y-axis.
Solution:
The radius of a disk is
Hence,
Answer: 32π/5 cubic units.
10.12 Volume by Cylindrical Shells
Another useful method for volumes of revolution is the cylindrical shell method. It is particularly convenient when vertical strips are rotated about the y-axis.
A vertical strip at position x generates a thin cylindrical shell with:
- radius x;
- height f(x);
- circumference 2πx;
- small thickness dx.
Therefore,
when the region lies between y=f(x) and the x-axis.
Question: Find the volume obtained when the region under
from x=0 to x=2 is rotated about the y-axis.
Formula:
Solution:
Since f(x)=x,
Answer: 16π/3 cubic units.
Question: The region under
for 0≤x≤2 is rotated about the y-axis. Find its volume using cylindrical shells.
Solution:
Answer: 8π cubic units.
10.13 Applications to Physical and Geometrical Problems
The formulas for areas and volumes are not restricted to purely abstract curves. They provide models for real geometric and physical structures whenever the dimensions can be represented by suitable functions.
Cross-Sectional Interpretation
If a solid has cross-sectional area A(x) at position x, then its volume over the interval [a,b] is
The disk and washer methods are special cases of this general principle.
Question: A solid extends from x=0 to x=3. Its cross-sectional area at position x is
square centimetres. Find the volume of the solid.
Formula:
Solution:
Answer: The volume is 15 cm3.
Recovering a Physical Quantity from a Rate
Question: Water enters a tank at a rate
litres per minute. Determine the amount of water added during the first 4 minutes.
Formula:
Solution:
Answer: 36 litres of water are added.
10.14 Choosing an Appropriate Area or Volume Method
Successful applications of integration depend on translating the geometry of the problem into an appropriate integral. The method should be chosen according to the orientation of the region and the axis of rotation.
| Problem Structure | Typical Integral | Main Idea |
|---|---|---|
| Area under a non-negative curve | ∫f(x)dx | Curve minus axis |
| Area between two curves using vertical strips | ∫[upper-lower]dx | Upper function minus lower function |
| Area using horizontal strips | ∫[right-left]dy | Right function minus left function |
| Rotation around an axis with no hole | π∫R2dx | Disk method |
| Rotation producing a central hole | π∫(R2-r2)dx | Washer method |
| Vertical strips rotated about y-axis | 2π∫(radius)(height)dx | Cylindrical shell method |
| Known cross-sectional area | ∫A(x)dx | Add cross-sectional volumes |
Before integrating, identify the boundaries of the region, determine the correct limits, decide which function is above or below the other, and identify the radius or height required for a volume calculation. A correctly evaluated integral cannot compensate for an incorrectly modelled region.
Question: Find the volume obtained when the region bounded by
is rotated about the x-axis.
Reasoning:
The region touches the axis of rotation, so each perpendicular cross-section is a disk rather than a washer.
Formula:
Solution:
Answer: The volume is π/5 cubic units.
Question: The region bounded by
between x=-2 and x=2 is rotated about the x-axis. Find the resulting volume.
Reasoning:
Rotation about the x-axis produces washers. The outer radius is 4 and the inner radius is x2.
Solution:
The integrand is even, so
Answer: The volume is 256π/5 cubic units.
Chapter Summary
- Definite integrals can be used to calculate exact geometric areas and volumes.
- If f(x)≥0, the area under y=f(x) from a to b is ∫abf(x)dx.
- When a curve lies below the x-axis, its definite integral is negative but its geometric area is positive.
- If a curve crosses the x-axis, total area should be found by dividing the interval at the zeros and adding positive regional areas.
- The area between two curves using vertical strips is obtained from ∫[upper-lower]dx.
- Using horizontal strips, the area between two curves is ∫[right-left]dy.
- Intersection points often determine the required limits of integration.
- A solid of revolution is formed when a plane region is rotated about an axis.
- The disk method gives V=π∫R2dx.
- The washer method gives V=π∫(R2-r2)dx.
- Rotation about the y-axis can sometimes be handled conveniently using integration with respect to y.
- The cylindrical shell method about the y-axis uses V=2π∫(radius)(height)dx.
- If the cross-sectional area of a solid is known as A(x), its volume is ∫A(x)dx.
- Correct modelling of the boundaries, limits, radii and heights is essential before evaluating an area or volume integral.
CHAPTER SEVEN
Systems of Particles, Centre of Mass and Relative Motion
7.1 Introduction to Systems of Particles
Many objects encountered in mechanics are not isolated particles. A car, a rigid body, a collection of interacting masses and even a planet may be regarded as a system made up of many particles. Instead of describing the motion of every individual particle separately, mechanics often simplifies the analysis by studying the system as a whole.
A system of particles is a collection of two or more particles regarded together for the purpose of mechanical analysis.
The particles within a system may exert forces on one another. They may also experience forces from objects outside the system. The distinction between these two kinds of force is fundamental.
7.2 Internal and External Forces
An internal force is a force exerted by one particle of a system on another particle within the same system.
An external force is a force exerted on the system by an object or agent that is not included in the chosen system.
Internal forces occur in equal and opposite pairs according to Newton's third law. Consequently, when the motion of the whole system is considered, internal forces cancel in pairs in the total force balance. The motion of the centre of mass is therefore controlled by the resultant external force.
Consider two blocks connected by a spring. If both blocks and the spring are included in the system, the spring forces are internal. If only one block is selected as the system, the spring force on that block becomes an external force.
7.3 Total Mass and Total Momentum of a System
For a system of particles with masses m1, m2, ..., mn, the total mass is
The total linear momentum of the system is the vector sum of the momenta of all its particles:
Question: Two particles of masses 3 kg and 5 kg move east at 4 m/s and west at 2 m/s respectively. Determine the total momentum of the system.
Given: Take east as positive.
Formula:
Solution:
Answer: The total momentum is 2 kg m/s east.
7.4 Centre of Mass of a System
The centre of mass provides a convenient single point with which to describe the overall translational motion of a system.
The centre of mass of a system is the point whose position is the mass-weighted average of the positions of all particles in the system.
For discrete particles,
The centre of mass need not coincide with the location of any actual particle. It may even lie outside the physical material of an object, as can occur for a ring.
7.5 Centre of Mass in One Dimension
For particles positioned along the x-axis,
Question: Three particles lie on the x-axis. A 2 kg particle is at x=0, a 3 kg particle is at x=4 m, and a 5 kg particle is at x=8 m. Find the centre of mass.
Formula:
Solution:
Answer: The centre of mass is at x=5.2 m.
Question: Two masses of 4 kg and 6 kg are separated by 5 m. Taking the 4 kg mass to be at x=0, find the centre of mass.
Solution:
Answer: The centre of mass lies 3 m from the 4 kg mass, or 2 m from the 6 kg mass.
7.6 Centre of Mass in Two and Three Dimensions
For a system distributed in a plane, the coordinates of the centre of mass are
and
For three-dimensional systems,
Question: A 2 kg particle is at (1,2) m and a 4 kg particle is at (7,5) m. Find the centre-of-mass coordinates.
Solution:
Answer: The centre of mass is at (5 m, 4 m).
7.7 Centre of Mass of Continuous Bodies
For an extended body whose mass is continuously distributed, the summation used for particles becomes an integral:
In one dimension,
If the body is uniform and possesses symmetry, the centre of mass often lies at the geometric centre. For example, the centre of mass of a uniform straight rod lies at its midpoint, while that of a uniform circular disc lies at its geometric centre.
Question: A uniform rod has length L and mass M. Show that its centre of mass is at its midpoint.
Solution:
For uniform linear density,
and
Therefore,
Answer: The centre of mass of a uniform rod is at L/2, its midpoint.
7.8 Motion of the Centre of Mass
The velocity of the centre of mass is obtained by differentiating its position:
For a system of particles,
Therefore, the total momentum is
Differentiating again gives
Question: A system consists of a 2 kg particle moving east at 6 m/s and a 3 kg particle moving east at 2 m/s. Find the velocity of the centre of mass.
Formula:
Solution:
Answer: The centre of mass moves at 3.6 m/s east.
7.9 Centre of Mass and Momentum Conservation
If the net external force on a system is zero,
Hence,
Therefore the centre of mass either remains at rest or moves with constant velocity. Internal interactions may be violent, as in an explosion, but they cannot alter the motion of the centre of mass of an isolated system.
Question: A stationary object explodes into several fragments. Describe the motion of the centre of mass if external forces are negligible during the explosion.
Solution:
Before the explosion, the total momentum is zero. Since external forces are negligible, total momentum remains zero.
Therefore,
Answer: The centre of mass remains at rest even though the fragments move apart.
7.10 Introduction to Relative Motion
Motion is always described with respect to a reference frame. An object may be stationary in one reference frame and moving in another. Relative motion provides a systematic way of relating observations made from different moving frames.
Relative motion is the motion of one object as observed from a reference frame attached to another object or moving system.
For example, a passenger sitting in a moving bus has zero velocity relative to the bus but a non-zero velocity relative to the road.
7.11 Relative Position and Relative Velocity
Let rA and rB be the position vectors of objects A and B relative to a common reference frame. The position of A relative to B is
Differentiating with respect to time,
Question: Car A moves east at 30 m/s while Car B moves east at 18 m/s. Find the velocity of A relative to B.
Formula:
Solution:
Answer: A moves at 12 m/s east relative to B.
Question: Car A travels east at 25 m/s while Car B travels west at 20 m/s. Find the velocity of A relative to B.
Solution:
Take east as positive:
Answer: A moves at 45 m/s east relative to B.
7.12 Relative Acceleration
Differentiating the relative velocity equation gives the acceleration of A relative to B:
If both objects have the same acceleration, their relative acceleration is zero, and their relative velocity remains constant.
Question: Vehicle A accelerates east at 4 m/s2, while Vehicle B accelerates east at 1.5 m/s2. Find the acceleration of A relative to B.
Solution:
Answer: The relative acceleration is 2.5 m/s2 east.
7.13 Relative Motion in One Dimension
When two objects move along the same straight line, relative motion can often be analysed by simple addition or subtraction of signed velocities.
Same Direction
For objects moving in the same direction, their relative speed is the difference between their speeds.
Opposite Directions
For objects moving towards one another, their closing speed is the sum of their speed magnitudes.
Question: Two trains are 900 m apart and move directly toward each other at 20 m/s and 25 m/s. How long before they meet?
Relative Speed:
Time:
Answer: The trains meet after 20 s.
Question: A car travelling at 30 m/s is 200 m behind another car travelling in the same direction at 20 m/s. Assuming constant velocities, how long will the faster car take to catch the slower one?
Relative Speed:
Time:
Answer: The faster car catches the slower car after 20 s.
7.14 Relative Motion in Two Dimensions
When motion occurs in a plane, relative velocity must be treated as a vector. Components are usually resolved along perpendicular axes and combined.
Question: Object A moves east at 8 m/s, while object B moves north at 6 m/s. Find the velocity of A relative to B.
Vector Velocities:
Relative Velocity:
Magnitude:
Direction:
Answer: A moves relative to B at 10 m/s, directed approximately 36.9° south of east.
7.15 Boats, Rivers, Wind and Moving Media
Relative velocity is particularly important when an object moves through a medium that is itself moving. Examples include a boat crossing a flowing river and an aircraft flying through moving air.
For a boat,
For an aircraft,
Question: A boat moves north through still water at 4 m/s. A river flows east at 3 m/s. Find the boat's velocity relative to the ground.
Components:
Magnitude:
Direction:
Answer: The boat moves at 5 m/s, approximately 36.9° east of north relative to the ground.
Question: A river is 120 m wide and flows east at 3 m/s. A boat is directed due north across the river with speed 4 m/s relative to the water. Find the crossing time and the downstream drift.
Crossing Time:
The northward component determines the time to cross:
Downstream Drift:
Answer: The boat takes 30 s to cross and drifts 90 m downstream.
Question: An aircraft has an airspeed of 200 km/h due north. A wind blows due east at 50 km/h. Find the aircraft's ground speed and direction.
Magnitude:
Direction:
Answer: The ground speed is approximately 206.2 km/h, directed 14.0° east of north.
The centre-of-mass method simplifies the motion of multi-particle systems, while relative motion explains how observations depend on the chosen reference frame. Both concepts are essential for understanding more advanced translational and rotational mechanics.
Chapter Summary
- A system of particles is a collection of particles analysed together.
- Internal forces act between particles inside the system, while external forces originate outside the chosen system.
- Total system momentum is the vector sum P=Σmivi.
- The centre of mass is the mass-weighted average position of a system.
- For discrete particles, rcm=Σmiri/M.
- For continuous bodies, centre-of-mass sums are replaced by integrals.
- The total momentum of a system is P=Mvcm.
- The centre-of-mass acceleration is determined by the resultant external force through ΣFext=Macm.
- If the net external force is zero, the centre of mass moves with constant velocity.
- Relative position is the difference between position vectors measured in a common frame.
- Relative velocity is vAB=vA-vB.
- Relative acceleration is aAB=aA-aB.
- Relative motion in two dimensions requires vector addition or subtraction.
- Boat-river and aircraft-wind problems are direct applications of relative velocity.
CHAPTER EIGHT
Rotational Motion, Torque and Angular Momentum
8.1 Introduction to Rotational Motion
Translational motion describes the movement of an object from one position to another. Rotational motion describes motion in which points of a body move around an axis. A rotating wheel, a ceiling fan, the hands of a clock and a spinning disc are familiar examples.
Many ideas from linear mechanics have rotational counterparts. Position corresponds to angular position, velocity to angular velocity, acceleration to angular acceleration, force to torque, mass to rotational inertia and linear momentum to angular momentum.
| Translational Quantity | Rotational Analogue |
|---|---|
| Position x | Angular position θ |
| Velocity v | Angular velocity ω |
| Acceleration a | Angular acceleration α |
| Force F | Torque τ |
| Mass m | Moment of inertia I |
| Linear momentum p | Angular momentum L |
8.2 Angular Position and Angular Displacement
The orientation of a rotating body can be described by an angular position θ, measured relative to a chosen reference line.
Angular displacement is the change in angular position of a rotating body.
The SI unit of angular displacement is the radian.
Hence,
Question: Convert 120° to radians.
Formula:
Solution:
Answer: 120°=2π/3 rad.
8.3 Angular Velocity
Angular velocity is the rate of change of angular position with time.
Average angular velocity is
Instantaneous angular velocity is
Its SI unit is radian per second, rad/s.
Question: A wheel turns through 20 rad in 4 s at uniform rate. Find its angular velocity.
Formula:
Solution:
Answer: The angular velocity is 5 rad/s.
8.4 Angular Acceleration
Angular acceleration is the rate of change of angular velocity with time.
Average angular acceleration is
Instantaneous angular acceleration is
Its SI unit is rad/s2.
Question: A disc increases its angular velocity uniformly from 4 rad/s to 16 rad/s in 3 s. Find its angular acceleration.
Formula:
Solution:
Answer: The angular acceleration is 4 rad/s2.
8.5 Rotational Kinematics
For constant angular acceleration, rotational motion obeys equations directly analogous to those of uniformly accelerated linear motion.
| Linear Motion | Rotational Motion |
|---|---|
| v=u+at | ω=ω0+αt |
| s=ut+(1/2)at2 | θ=ω0t+(1/2)αt2 |
| v2=u2+2as | ω2=ω02+2αθ |
| s=(u+v)t/2 | θ=(ω0+ω)t/2 |
Question: A wheel starts from rest and accelerates uniformly at 3 rad/s2 for 5 s. Find its final angular velocity and angular displacement.
Given:
Final Angular Velocity:
Angular Displacement:
Answer: Final angular velocity = 15 rad/s; angular displacement = 37.5 rad.
8.6 Relationship Between Linear and Angular Quantities
For a point at distance r from a fixed axis of rotation, the arc length travelled is
provided θ is measured in radians.
Differentiating with respect to time gives
For tangential acceleration,
A point moving in a circle also has radial or centripetal acceleration
Question: A point on the rim of a wheel of radius 0.40 m rotates with angular velocity 12 rad/s. Find its linear speed.
Formula:
Solution:
Answer: The linear speed is 4.8 m/s.
Question: A rotating disc has radius 0.25 m and angular acceleration 8 rad/s2. Find the tangential acceleration of a point at the rim.
Formula:
Solution:
Answer: The tangential acceleration is 2 m/s2.
8.7 Torque and Moment of a Force
A force can change the translational motion of a body, but its ability to produce rotation depends on where and how the force is applied.
Torque, also called the moment of a force, measures the turning effect of a force about a point or axis.
The magnitude of torque is
where r is the distance from the axis to the point of application, F is the force magnitude and θ is the angle between r and F.
Equivalently,
where r⊥ is the perpendicular moment arm.
Question: A force of 40 N acts perpendicular to a spanner at a distance of 0.30 m from the pivot. Find the torque.
Formula:
Solution:
Answer: The torque magnitude is 12 N m.
Question: A 25 N force is applied to a 0.50 m lever at an angle of 30° to the lever. Find the torque magnitude.
Solution:
Answer: The torque magnitude is 6.25 N m.
8.8 Torque as a Vector Product
Torque is a vector quantity and is defined by the cross product
Its direction is perpendicular to the plane containing r and F, determined by the right-hand rule.
In two-dimensional mechanics, counterclockwise torque is often assigned a positive sign and clockwise torque a negative sign, although the sign convention may be reversed if used consistently.
Question: A force
acts at position
Find the torque about the origin.
Formula:
Solution:
Answer: τ=12k N m.
8.9 Rotational Form of Newton's Second Law
For a rigid body rotating about a fixed axis, the rotational analogue of Newton's second law is
where I is the moment of inertia about the axis and α is the angular acceleration.
The moment of inertia measures resistance to angular acceleration. Its detailed calculation and standard forms will be developed further in the next chapter.
Question: A wheel has moment of inertia 2.5 kg m2. A net torque of 10 N m acts on it. Find its angular acceleration.
Formula:
Solution:
Answer: The angular acceleration is 4 rad/s2.
8.10 Angular Momentum of a Particle
The angular momentum of a particle about a point is the vector product of its position vector and linear momentum.
Since p=mv,
The magnitude is
If the particle moves perpendicular to the radius vector,
The SI unit of angular momentum is
Question: A 2 kg particle moves at 5 m/s perpendicular to a radius vector of magnitude 3 m. Find its angular momentum about the origin.
Formula:
Solution:
Answer: The angular momentum magnitude is 30 kg m2/s.
8.11 Angular Momentum of a Rigid Body
For a rigid body rotating about a fixed principal axis, the angular momentum may be written as
This is analogous to the translational relation
The relation L=Iω is especially useful when the angular momentum is parallel to the rotation axis.
Question: A rotating body has moment of inertia 4 kg m2 and angular velocity 6 rad/s. Find its angular momentum.
Formula:
Solution:
Answer: The angular momentum is 24 kg m2/s.
8.12 Conservation of Angular Momentum
Torque is related to the time rate of change of angular momentum:
If the resultant external torque is zero,
and therefore
When the resultant external torque on a system is zero, the total angular momentum of the system remains constant.
For rotation about a fixed axis,
Question: A rotating skater has moment of inertia 5 kg m2 and angular speed 2 rad/s. By drawing in the arms, the moment of inertia decreases to 2 kg m2. Neglect external torque. Find the new angular speed.
Formula:
Solution:
Answer: The new angular speed is 5 rad/s.
When external torque is negligible, reducing moment of inertia increases angular velocity so that angular momentum remains constant. This explains why a spinning skater rotates faster after drawing the arms inward.
8.13 Rotational Work, Energy and Power
A torque acting through angular displacement can perform rotational work. For a constant torque,
provided torque and angular displacement correspond to the same rotational direction.
The rotational kinetic energy of a rigid body rotating about a fixed axis is
The rotational form of the work-energy theorem is
Rotational power is
Question: A wheel with moment of inertia 3 kg m2 rotates at 8 rad/s. Find its rotational kinetic energy.
Formula:
Solution:
Answer: The rotational kinetic energy is 96 J.
Question: A motor applies a torque of 15 N m to a shaft rotating at 20 rad/s. Find the mechanical power transmitted.
Formula:
Solution:
Answer: The power transmitted is 300 W.
8.14 Rotation of Coordinate Axes
Sometimes it is useful to describe the same point using a new coordinate system whose axes have been rotated relative to the original axes. This does not change the physical point; it changes only the coordinates used to describe it.
Suppose the new axes x' and y' are obtained by rotating the original axes counterclockwise through an angle φ. The coordinates are related by
and
Conversely,
and
The distance from the origin remains unchanged:
Question: A point has coordinates (x,y)=(3,4). The coordinate axes are rotated counterclockwise by 90°. Find (x',y').
Formula:
Solution: For φ=90°,
Answer: The coordinates in the rotated system are (4,-3).
8.15 Polar Coordinates
Cartesian coordinates locate a point using perpendicular distances x and y. For rotational and circular motion, polar coordinates are often more natural.
Polar coordinates specify the position of a point in a plane by its radial distance r from the origin and its angular coordinate θ measured from a chosen reference direction.
The relationship between Cartesian and polar coordinates is
and
Conversely,
and, with the quadrant taken into account,
Question: Convert the Cartesian point (3,4) to polar coordinates.
Radial Coordinate:
Angular Coordinate:
Answer: The polar coordinates are approximately (5, 53.1°).
Unit Vectors in Polar Coordinates
In planar polar coordinates, the unit vectors are er in the radial direction and eθ in the direction of increasing angle.
Unlike the fixed Cartesian unit vectors, these unit vectors change direction as the particle moves around the origin. Their time derivatives are
and
Velocity in Polar Coordinates
For position
the velocity is
Thus, motion may contain both a radial component and a transverse component.
Acceleration in Polar Coordinates
The acceleration is
For uniform circular motion, r is constant, ṙ=0, r̈=0 and θ̇=ω is constant. Therefore,
which is the familiar centripetal acceleration directed toward the centre.
8.16 Applications of Rotational Dynamics
Rotational mechanics combines angular kinematics, torque, rotational inertia, angular momentum and energy methods. These concepts allow the analysis of wheels, pulleys, rotating shafts, gears, flywheels and many other mechanical systems.
Question: A rotating wheel has moment of inertia 5 kg m2. A constant net torque of 20 N m acts for 4 s. If the wheel starts from rest, find its angular acceleration, final angular velocity and angular displacement.
Angular Acceleration:
Final Angular Velocity:
Angular Displacement:
Answer: Angular acceleration = 4 rad/s2; final angular velocity = 16 rad/s; angular displacement = 32 rad.
Question: A wheel of radius 0.50 m rotates at 10 rad/s. Find the linear speed and centripetal acceleration of a point on its rim.
Linear Speed:
Centripetal Acceleration:
Answer: Linear speed = 5 m/s; centripetal acceleration = 50 m/s2 toward the centre.
Question: A rigid body has rotational kinetic energy 200 J and moment of inertia 4 kg m2. Find its angular speed.
Formula:
Solution:
Answer: The angular speed is 10 rad/s.
Rotational motion has a mathematical structure closely parallel to translational motion. Torque produces angular acceleration, rotational inertia measures resistance to angular acceleration, and angular momentum is conserved when external torque is zero. These ideas lead naturally to the detailed study of circular motion and moments of inertia.
Chapter Summary
- Rotational motion describes motion about an axis.
- Angular displacement is measured in radians, with 2π rad=360°.
- Angular velocity is ω=dθ/dt, while angular acceleration is α=dω/dt.
- For constant angular acceleration, rotational kinematics has equations analogous to linear kinematics.
- Linear and angular quantities are related by s=rθ, v=rω and at=rα.
- Radial acceleration in circular motion is ar=ω2r=v2/r.
- Torque measures the turning effect of a force and has magnitude τ=rFsinθ.
- Vector torque is τ=r×F.
- For rotation about a fixed axis, Στ=Iα.
- The angular momentum of a particle is L=r×p.
- For a rigid body rotating about a fixed principal axis, L=Iω.
- Angular momentum is conserved when the resultant external torque is zero.
- Rotational kinetic energy is K=(1/2)Iω2.
- Rotational power is P=τω.
- Rotating coordinate axes provide an alternative description of the same physical point.
- Polar coordinates use radial distance and angle to describe positions in a plane.
- Polar-coordinate velocity contains radial and transverse components, while polar-coordinate acceleration contains corresponding radial and transverse terms.